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Question
A ray of light enters a glass slab ABDC as shown in figure and strikes at the centre O of the circular part AC of the slab. The critical angle of glass is 42°. Complete the path of the ray till it emerges out from the slab. Mark the angles in the diagram wherever necessary.
Solution
Inside the slab at K ∠i = 48° = ∠r
KL incident ray strikes at L, ∠i = 42° = ∠C and emergent ray LM is parallel to BD, i.e. ∠r = 90°
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|
S. No. |
∠i |
∠i |
∠e |
|
I |
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