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A reaction is second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant is reduced to half? - Chemistry

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Question

A reaction is second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant is reduced to half?

Numerical

Solution

Rate of reaction, R = k [A]2

If [A] = `1/2`R, rate = `"k"("R"/2)^2`

= `1/4`kR2

i.e. rate becomes `1/4`th when concentration is reduced to `1/2`.

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