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Question
A sample of 100 items, draw from a universe with mean value 4 and S.D 3, has a mean value 63.5. Is the difference in the mean significant at 0.05 level of significance?
Solution
Sample size n = 100
Sample mean `bar(x)` = 63.5
Sample SD S = 3
Population mean µ = 64
Population SD σ = 3
Null Hypothesis H0: µ = 64 .....(the sample has been drawn from the population mean µ = 64 and SD σ = 3)
Alternative Hypothesis H1: µ ≠ 64 ....(two tail)
i.e The sample has not been drawn from the population mean µ = 64 and SD σ = 3
The level of significance α = 5% = 0.05
Test statistic z = `(63.5 - 64)/(3/sqrt(100)`
= `(-0.5)/((3/10))`
= `(-0.5)/0.3`
= - 1.667
`|z| = 1.667`
∴ calculated z = 1.667
critical value at 5% level of significance is `"z"_("a"/2)` = 1.96
Inference:
At 5% level of significance `"Z" < "Z"_("a"/2)`
Since the calculated value is less than the table value the null hypothesis is accepted.
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