English
Karnataka Board PUCPUC Science Class 11

A Scooter Starting from Rest Moves with a Constant Acceleration for a Time ∆T1, Then with a Constant Velocity for the Next ∆T2 And Finally with a Constant Deceleration for the Next - Physics

Advertisements
Advertisements

Question

A scooter starting from rest moves with a constant acceleration for a time ∆t1, then with a constant velocity for the next ∆t2 and finally with a constant deceleration for the next ∆t3 to come to rest. A 500 N man sitting on the scooter behind the driver manages to stay at rest with respect to the scooter without touching any other part. The force exerted by the seat on the man is

Options

  • 500 N throughout the journey

  • less than 500 N throughout the journey

  • more than 500 N throughout the journey

  • > 500 N for time ∆t1 and ∆t3 and 500 N for ∆t2.

MCQ

Solution

>500 N for time ∆t1 and ∆t3 and 500 N for ∆t2.

During the time interval ∆t2, the scooter is moving with a constant velocity, which implies that the force exerted by the seat on the man is 500 N (for balancing the weight of the man).
During the time interval ∆t1 and ∆t3, the scooter is moving with constant acceleration and deceleration, which implies that a frictional force is also applied. Therefore, the net force exerted by the seat on the man should be >500 N.

shaalaa.com
  Is there an error in this question or solution?
Chapter 6: Friction - MCQ [Page 96]

APPEARS IN

RELATED QUESTIONS

Can you accelerate a car on a frictionless horizontal road by putting more petrol in the engine? Can you stop a car going on a frictionless horizontal road by applying brakes?


Two cars of unequal masses use similar tyres. If they are moving at the same initial speed, the minimum stopping distance


In order to stop a car in shortest distance on a horizontal road, one should


Consider a vehicle going on a horizontal road towards east. Neglect any force by the air. The frictional force on the vehicle by the road
(a) is towards east if the vehicle is accelerating
(b) is zero if the vehicle is moving with a uniform velocity
(c) must be towards east
(d) must be towards west.


A care is going at a speed of 21.6 km/hr when it encounters at 12.8 m long slope of angle 30° (in the following figure). The friction coefficient between the road and the tyre is `1/2sqrt3`. Show that no matter how hard the driver applies the brakes, the car will reach the bottom with a speed greater than 36 km/hr. Take g = 10 m/s2.


A car starts from rest on a half kilometre long bridge. The coefficient of friction between the tyre and the road is 1.0. Show that one cannot drive through the bridge in less than 10 s.


A disc of mass M and radius R is placed a rough horizontal surface with its axis horizontal. A light rod of length '2R' is fixed to the disc at point 'A' as shown in figure and a force `3/2` Mg is applied at the other end. If disc starts to roll without slipping the value of "10 × µmin" where µmin is minimum coefficient of friction between disc and horizontal surface required for pure rolling is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×