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Question
A simple machine enables us to lift a load of 10,000 N by the application of an effort of 500 N. However, when the point of application of the effort moves through 2.5 m, the load gets raised through 10 cm only. What are the values of the:
(i) M.A.
(ii) V.R. and
(iii) Efficiency of the machine?
Solution
(i) M.A. = `"Load"/"Effort"=(10,000"N")/(500"N")=20`
(ii) V.R. =`"Distance moved by the effort"/"Distance moved by the load"`
`=(2.5"m")/((10//100)"m")=25.`
(iii) Efficiency =`"M.A."/"V.R."=20/25=4/5=4/5xx100%=80%.`
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