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Karnataka Board PUCPUC Science Class 11

A Solid Sphere Rolling on a Rough Horizontal Surface with a Linear Speed ν Collides Elastically with a Fixed, Smooth, Vertical Wall. - Physics

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Question

A solid sphere rolling on a rough horizontal surface with a linear speed ν collides elastically with a fixed, smooth, vertical wall. Find the speed of the sphere after it has started pure rolling in the backward direction.

Sum

Solution

Consider two cases:-

(a) Just after the collision with the wall, the sphere rebounds with velocity \[\nu\] towards left but it continues to rotate in the clockwise direction (as shown in figure)

Angular momentum of the sphere about centre,

\[L = mvR - I\omega\]

\[     = mvR - \frac{2}{5}m R^2  \times \frac{\nu}{R}\]

\[     = \frac{3}{5}mvR\]

(b) When pure rolling starts

Let the velocity be \[\nu'\] and the corresponding angular velocity be \[\frac{v'}{R}.\]

\[L' = mv'R + I\omega'\]

\[     = mv'R + \frac{2}{5}m R^2  \times \frac{v'}{R}\]

\[     = \frac{7}{5}mv'R\]

Angular momentum is constant.

Therefore, we have

\[L = L'\]

\[ \Rightarrow v' = \frac{3v}{7}\]

So, the sphere will move with velocity \[\frac{3v}{7}.\]

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Chapter 10: Rotational Mechanics - Exercise [Page 200]

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HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 10 Rotational Mechanics
Exercise | Q 86 | Page 200

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