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Question
A solution containing 15 g urea (molar mass = 60 g mol–1) per litre of solution in water has the same osmotic pressure (isotonic) as a solution of glucose (molar mass = 180 g mol–1) in water. Calculate the mass of glucose present in one litre of its solution.
Solution 1
For isotonic solution
π1 = π2
C1 = C2 (at same temperature)
or n1 = n2 (is same volume)
`15/60=x/180`
x = 45 g, mass of glucose per liter of solution.
Solution 2
Osmotic pressure π = CRT =`(n2)/VRT`
where n is the number of moles of solute present in volume V of solvent.
It is given that the solution of urea is isotonic with the solution of glucose, thus
`(n_`
`=>(n_`
`=>(w_`
`=>w_`
Hence, the mass of glucose present in one litre of its solution = 45 g
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