Advertisements
Advertisements
Question
A string of length `l` is fixed at one end and carries a mass 'm' at the other end. The mass is revolving along a horizontal circle of radius 'r' making 'θ' as the semi-vertical angle of cone and `(1/pi)` revolutions per second around the vertical axis through fixed end. The tension in the string is ______.
Options
2 ml
8 ml
4 ml
16 ml
Solution
A string of length `l` is fixed at one end and carries a mass 'm' at the other end. The mass is revolving along a horizontal circle of radius 'r' making 'θ' as the semi-vertical angle of cone and `(1/pi)` revolutions per second around the vertical axis through fixed end. The tension in the string is 4 ml.
Explanation:
Frequency `f=1/pi` rps, ω = 2πf = `2pixx1/pi `= 2 rad/s
In a conical pendulum, the horizontal component of the tension Tsinθ provides the centripetal force.
∴ Tsinθ = mrω2
but r = Lsinθ and ω2 = 4
∴ T = 4mL