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Question
A student gets 31% marks in an examination but fails by 12 marks. If the pass percentage is 35%, find the maximum marks of the examination.
Solution
Let the maximum marks in the exam be ‘x’
Pass percentage is given as 35%
∴ Pass mark = `35/100 xx x = 35/100 x`
Student gets 31% marks = `31/100 xx x = 31/100 x`
But student fails by 12 marks → meaning his mark is 12 less than pass mark.
∴ `31/100 x = 35/100 x - 12`
∴ `35/100 x - 31/100 x` = 12
∴ `(35x - 31x)/100` = 12
⇒ `(4x)/100` = 12
∴ x = `(12 xx 100)/4`
= 300
Maimum mark is 300
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