Question

A suitcase with measures 80 cm × 48 cm × 24 cm is to be covered with a tarpaulin cloth. How many metres of tarpaulin of width 96 cm is required to cover 100 such suitcases?

Answer 1

Length of suitcase (l) = 80 cm

Width of suitcase (b) = 48 cm

Height of suitcase (h) = 24 cm

Width of tarpaulin = 96 cm

Then total surface area of the suitcase = 2(lb + bh + hl)

= 2(80 × 48 + 48 × 24 + 24 × 80)

= 2(3840 + 1152 + 1920)

= 2 × 6912

= 13824 cm²

The tarpaulin required to cover the suitcase will be equal to the area of the suitcase.

Then area of tarpaulin = total surface area of suitcase

l × b =13824

l × 96 = 13824

l=`13824/96`

l = 144 cm

Hence, tarpaulin required to cover 100 suitcases:

= 144 × 100

= `144/100 xx100`

= 144 m.