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A Swimming Pool is 20 M Long 15 M Wide and 3 M Deep. Find the Cost of Repairing the Floor and Wall at the Rate of Rs 25 per Square Metre. - Mathematics

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Question

A swimming pool is 20 m long 15 m wide and 3 m deep. Find the cost of repairing the floor and wall at the rate of Rs 25 per square metre.

Answer in Brief

Solution

\[\text { Length of the swimming pool = 20 m }\]

\[\text { Breadth = 15 m}\]

\[\text { Height = 3 m }\]

\[\text { Now, surface area of the floor and all four walls of the pool = (length } \times \text { breadth) } + 2 \times \text { (breadth } \times \text { height + length } \times\text {  height) }\]

\[ = (20 \times 15) + 2 \times (15 \times 3 + 20 \times 3)\]

\[ = 300 + 2 \times (45 + 60)\]

\[ = 300 + 210\]

\[ = 510 m^2 \]

\[\text { The cost of repairing the floor and the walls is Rs } 25 m^2 . \]

\[ \therefore\text {  The total cost of repairing 510 m^2 area = 510} \times 25 = \text { Rs } 12750\] 

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Chapter 21: Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube) - Exercise 21.3 [Page 22]

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RD Sharma Mathematics [English] Class 8
Chapter 21 Mensuration - II (Volumes and Surface Areas of a Cuboid and a Cube)
Exercise 21.3 | Q 11 | Page 22
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