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Question
A train starting from rest moves with a uniform acceleration of 0.2 m/s2 for 5 minutes. Calculate the speed acquired and the distance travelled in this time.
Solution
We have to find the distance travelled as well as final velocity of the train. We have the following information given,
Initial velocity, (u) = 0 m/s
Acceleration for the entire journey, (a) = 0.2 m/s2
Time taken,
(t) = (5) (60) s
= 300 s
So, we can find the final velocity using the relation,
v = u + at
Therefore, final velocity of the train is,
v = 0 + (0.2)(300)
= 60 m/s
We can calculate the distance travelled by the train, using the 2nd equation of motion,
`s = ut + 1/2at^2`
Put the values in above equation to find the distance travelled,
`(s) = 0(300) + 1/2(0.2)(300)^2`
= (9000) m
= 9 km
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