Advertisements
Advertisements
Question
A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of 400 m in 20 s. Find its acceleration. Find the force acting on it if its mass is 7 metric tonnes (Hint: 1 metric tonne = 1000 kg).
Solution
Distance covered by the truck (s) = 400 m
Time (t) = 20 s
Initial velocity (u) = 0
Mass of the truck: m = 7 tons = 7000 kg (1 metric ton = 1000 kg)
According to the second equation of motion
S = ut + 12at2
400 = 0 × 20 + 12 × a × (20)2
a = 2m/s2
Hence, acceleration of the truck = 2m/s2
Since force (F) = mass × acceleration (a),
F = 7000 × 2
F = 14000N
Hence, force applied on the truck = 14000 N
APPEARS IN
RELATED QUESTIONS
A bullet of mass 10 g travelling horizontally with a velocity of 150 m s−1 strikes a stationary wooden block and comes to rest in 0.03 s. Calculate the distance of penetration of the bullet into the block. Also calculate the magnitude of the force exerted by the wooden block on the bullet.
How much momentum will a dumb-bell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be 10 m s−2.
A large truck and a car, both moving with a velocity of magnitude v, have a head-on collision and both of them come to a halt after that. If the collision lasts for 1 s:-
(a) Which vehicle experiences the greater force of impact?
(b) Which vehicle experiences the greater change in momentum?
(c) Which vehicle experiences the greater acceleration?
(d)Why is the car likely to suffer more damage than the truck?
Explain the meaning of the following equation :
F = m x a
where symbols have their usual meanings
A body of mass 5 kg is moving with a velocity of 10 m/s. A force is applied to it so that in 25 seconds, it attains a velocity of 35 m/s. Calculate the value of the force applied.
A car of mass 2400 kg moving with a velocity of 20 m s-1 is stopped in 10 seconds on applying brakes. Calculate the retardation and the retarding force.
The acceleration produced by a force of 5 N acting on a mass of 20 kg in m/s2 is :
Which of the following situations involves the Newton's second law of motion?
Deduce the equation of a force using Newton’s second law of motion.
Two blocks each of mass m lie on a smooth table. They are attached to two other masses as shown in the figure. The pulleys and strings are light. An object O is kept at rest on the table. The sides AB and CD of the two blocks are plane and made reflecting. The acceleration of two images formed in those two reflecting surfaces with respect to each other is ______.
