Advertisements
Advertisements
Question
A woman reduces her weight in the ratio 7 : 5. What does her weight become if originally it was 91 kg.
Solution
Ratio between the original weight and reduced weight = 7 : 5
Let original weight = 7x
then reduced weight = 5x
If original weight = 91 kg
then reduced weight
= `(91 xx 5x)/(7x)`
= 65 kg.
APPEARS IN
RELATED QUESTIONS
Find sub-triplicate ratio of x3 : 125y3
Convert the following percentage to fractions and ratio:
0.3%
Find the duplicate ratio of the following :
`2/3 : 4/9`
Find the triplicate ratio of the following :
`2 sqrt 5 : 5 sqrt 2`
If `(7"m" + 2"n")/(7"m" - 2"n") = 5/3` use properties of proportion to find:
(i) m : n
(ii) `("m"^2 + "n"^2)/("m"^2 - "n"^2)`
Express the following ratios in its simplest form :
5 kg: 800 gm
Arrange 5: 6, 8: 9, 13: 18 and 7: 12 in ascending order of magnitude.
Solve for x: `(3x^2 + 5x + 18)/(5x^2 + 6x + 12) = (3x + 5)/(5x - 6)`.
The cost of parking a bicycle is ₹ 5 and the cost of parking a scooter is ₹ 15. Find the simplest ratio of the parking cost of a bicycle to that of a scooter
Given below is a Mathematical term.
Find the ratio of consonants to vowels in the term.
