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Question
Ammonia burns in oxygen and the combustion, in the presence of a catalyst, may be represented by;
\[\ce{2NH3 + 2 1/2O2 -> 2NO + 3H2O}\] [H = 1, N = 14, O = 16]
What mass of steam is produced when 1.5 g of nitrogen monoxide is formed?
Solution
From equation, \[\ce{2NH3 + 2 1/2O2 -> 2NO + 3H2O}\]
When 60 g NO is formed, the mass of steam produced = 54 g
So, 1.5 g NO is formed, the mass of steam produced = `54 xx 1.5/60`
= 1.35 g
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