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Question
An element with density 10 g cm−3 forms a cubic unit cell with edge length of 3 × 10−8 cm. What is the nature of the cubic unit cell if the atomic mass of the element is 81 g mol−1?
Solution
Given:
Density (D) = 10 g/cm3
Edge length (a) = 3 x 10−8 cm
Atomic mass = 81 g/mol
Formula:
`10=(Zxx81)/((3xx10)^3xx6.022xx10^23)`
`Z=(10xx(3xx10)^3xx6.022xx10^23)/81=2.0073`
∴ Z = 2
The unit cell contains 2 atoms, so it is a body-centred cubic unit cell.
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