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Question
Answer the following in one or two sentences.
Which of the following solution will have higher freezing point depression and why?
i. 0.1 m NaCl
ii. 0.05 m Al2(SO4)3
Solution
For 0.1 m NaCl:
NaCl → Na+ + Cl-
0.1 m 0.1 m 0.1 m
Total particles in solution = 0.2 mol
For 0.05 m Al2(SO4)3:
Al2(SO4)3 → 2Al3+ + 3`"SO"_4^(2-)`
0.05 m 0.1 m 0.15 m
Total particles in solution = 0.25 mol
Al2(SO4)3 solution contains more number of particles than NaCl solution. Hence, Al2(SO4)3 solution has maximum ΔTf.
Therefore, the freezing point depression of 0.05 m Al2(SO4)3 solution will be higher than 0.1 m NaCl solution.
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