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Question
Answer the following question:
Find the area of triangle whose vertices are L(1, 1), M(−2, 2), N(5, 4)
Solution
Here, L(x1, y1) ≡ L(1, 1), M(x2, y2) ≡ M(–2, 2), N(x3, y3) ≡ N(5, 4)
Area of a triangle = `1/2|(x_1, y_1, 1),(x_2, y_2, 1),(x_3, y_3, 1)|`
∴ A(ΔLMN) = `1/2|(1, 1, 1),(-2, 2, 1),(5, 4, 1)|`
= `1/2[1(2 - 4) - 1 (-2 - 5) + 1(-8 - 10)]`
= `1/2[1(-2) - 1 (- 7) + 1 (- 18)]`
= `1/2(-2 + 7 - 18)`
= `-13/2`
Since area cannot be negative,
A(ΔLMN) = `13/2"sq. units"`
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