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Question
Answer the following question in detail.
What is achromatism? Derive a condition to achieve achromatism for a lens combination. State the conditions for it to be converging.
Solution
- To eliminate chromatic aberrations for extreme colours from a lens, either a convex and a concave lens in contact or two thin convex lenses with proper separation are used.
- This combination is called an achromatic combination. The process of using this combination is termed as achromatism of a lens.
- Let ω1 and ω2 be the dispersive powers of materials of the two-component lenses used in contact for an achromatic combination.
- Let V, R and Y denote the focal lengths for violet, red and yellow colours respectively.
- For lens 1, let
K1 = `(1/"R"_1-1/"R"_2)_1` and K2 = `(1/"R"_1-1/"R"_2)_2` - For the combination to be achromatic, the resultant focal length of the combination must be the same for both the colours,
∴ fV = fR
∴ `1/"f"_"V"=1/"f"_"R"`
For two thin lenses in contact, `1/"f"=1/"f"_1+1/"f"_2`
∴ `1/("f"_"V")_1+1/(("f"_"V")_2)=1/("f"_"R")_1+1/(("f"_"R")_2)` - From Lens maker’s formula,
[(nV)1 − 1]K1 + [(nV)2 − 1]K2 = [(nR)1 − 1]K1 + [(nR)2 −1]K2
∴ `"K"_1/"K"_2=(("n"_"V")_2-("n"_"R")_2)/(("n"_"V")_1-("n"_"R")_1)` ....(1) - Similarly, for mean colour (yellow),
`1/"f"_"Y"=1/(("f"_"Y")_1)+1/(("f"_"Y")_2)` ...(2)
`"K"_1/"K"_2=(("n"_"Y")_2-1)/(("n"_"Y")_1-1)xx(("f"_"Y")_2)/(("f"_"Y")_1)` ....(3) - From equations (1) and (3)
`(("f"_"Y")_2)/(("f"_"Y")_1)=-(("n"_"V")_2-("n"_"R")_2)/(("n"_"V")_1-("n"_"R")_1)xx(("n"_"Y")_2-1)/(("n"_"Y")_1-1)` ...(4)
Now, dispersive power ω1 = `(("n"_"V")_2-("n"_"R")_2)/(("n"_"Y")_2-1)` and
ω2 = `(("n"_"V")_2-("n"_"R")_2)/(("n"_"Y")_2-1)` - Substituting values of ω1 and ω2 in equation (4), we get,
`(("f"_"Y")_2)/(("f"_"Y")_1)=ω_2/ω_1`
This is the condition for achromatism of a combination of lenses.
Condition for converging:
For this combination to be converging, fY must be positive.
Using equation (3), for fY to be positive,
(fY)1 < (fY)2 ⇒ ω1 < ω2
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