Advertisements
Advertisements
Question
Answer the following question.
Obtain the expression for the ratio of the de-Broglie wavelengths associated with the electron orbiting in the second and third excited states of the hydrogen atom.
Solution
Second excited state (n = 3)
Third excited state (n = 4)
We know that,
`E = "hc"/λ`
`(13.6)/(n^2) = "hc"/λ`
`(13.6)/("n"^2"hc") = 1/λ`
`λ = ("n"^2"hc")/(13.6)`
Now,
`λ_2/λ_3 = ("n"_2^2"hc")/(13.6) xx (13.6)/("n"_3^2"hc")`
`λ_2/λ_3 = ("n"^2 2)/("n"^2 3) = (3)^2/(4)^2`
`λ_2/λ_3 = (9)/(16)`
`λ_2 : λ_3 = 9: 16`
APPEARS IN
RELATED QUESTIONS
Calculate the de Broglie wavelength of an electron moving with - of the speed of light in vacuum (Negelct relativistic effect)
(Planck's constant: h = 6.63 x 10-34 Js, Mass of electron : m = 9.11 x 10-28 g)
State how de-Broglie wavelength (`lambda`) of moving particles varies with their linear momentum (p).
An electron is accelerated from rest through a potential V. Obtain the expression for the de-Broglie wavelength associated with it ?
A proton and an electron have same velocity. Which one has greater de-Broglie wavelength and why?
Describe in brief what is observed when moving electrons are allowed to fall on a thin graphite film and the emergent beam falls on a fluorescent screen.
Gas exerts pressure on the walls of the container because :
Two bodies A and B having masses in the ratio of 3 : 1 possess the same kinetic energy. The ratio of linear momentum of B to A is:
Find the de-Broglie Wavelength for an electron moving at the speed of 5.0 × 106 m/s. (mass of electron is 9.1 × 10-31)
Number of ejected photo electrons increase with increase
An oil drop carrying a charge q has a mass m kg it is falling freely in air with terminal speed v. the electron field required to make the drop move upward with the same speed is