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Question
Arrange the given fractions in descending order of magnitude:
`5/7,3/8,9/11`
Solution
`5/7,3/8,9/11`
L.C.M. of numerator 5, 3, 9 = 45
| 3 | 5, | 3, | 9 |
| 5 | 5, | 1, | 3 |
| 3 | 1, | 1, | 3 |
| 1, | 1, | 1 |
= 3 × 5 × 3 = 45
`∴5/7=(5xx9)/(7xx9)=45/63;3/8=(3xx15)/(8xx15)=45/120`
`9/11=(9xx5)/(11xx5)=45/55`
We know that the numerator being the same, the fraction having the smallest denominator is the biggest fraction.
∴ `45/55,45/63,45/120`
i.e. `9/11,5/7,3/8`
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