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Question
Arul, Madan and Ram working together can clean a store in 6 hours. Working alone, Madan takes twice as long to clean the store as Arul does. Ram needs three times as long as Arul does. How long would it take each if they are working alone?
Solution
Let the time taken by Arul be “x” hours
Let the time taken by Madan be “y” hours
Let the time taken by Ram be “z” hours
By the given first condition
`1/x + 1/y + 1/z = 1/6`
Again by the given second condition
`1/x = 2 xx 1/y`
`1/x - 2/y` = 0
By the given third condition
`3 xx 1/z = 1/x`
`- 1/x + 3/z` = 0
Let `1/x` = a, `1/y` = b, `1/z` = c
a + b + c = `1/6`
6a + 6b + 6c = 1 ...(1)
a – 2b = 0 ...(2)
– a + 3c = 0 ...(3)
(1) × 1 ⇒ 6a + 6b + 6c = 1 ....(1)
(2) × 3 ⇒ 3a – 6b + 0 = 0 ....(2)
(1) + (2) ⇒ 9a + 6c = 1 ....(4)
(3) × (2) ⇒ – 2a + 6c = 0 ....(3)
(–) (–) (–)
(4) – (3) ⇒ 11a = 1 ⇒ a = `1/11`
Substitute the value of a = `1/11` in (2)
`1/11 - 2"b"` = 0
`1/11` = 2b ⇒ b = `1/22`
Substitute the value of a in (3)
`- 1/11 + 3"c"` = 0 ⇒ 3c = `1/11` ⇒ c = `1/33`
But `1/x` = a `1/x = 1/11` x = 1 |
`1/y` = b `1/y = 1/22` y = 22 |
`1/z` = c `1/z = 1/33` y = 33 |
Arul take 11 hours, Madan take 22 hours and Ram takes 33 hours.
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