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Question
By using determinant, show that the following points are collinear: P(5, 0), Q(10, –3), R(–5, 6)
Sum
Solution
Here, P(x1, y1) ≡ P(5, 0), Q(x2, y2) ≡ Q(10, –3), R(x3, y3) ≡ R(–5, 6)
If A(ΔPQR) = 0, then the points P, Q, R are collinear.
∴ A(ΔPQR) = `1/2|(5, 0, 1),(10, -3, 1),(-5, 6, 1)|`
= `1/2[5(-3 - 6) - 0(10 + 5) + 1(60 - 15)]`
= `1/2(-45 + 0 + 45)` = 0
∴ A(ΔPQR) = 0
∴ Points P, Q and R are collinear.
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Collinearity of Three Points
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