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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 6

By using the following clues, find who am I? i) Each of my numerator and denominator is a single digit number. ii) The sum of my numerator and denominator is a multiple of 3. iii) The product - Mathematics

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Question

By using the following clues, find who am I?

i) Each of my numerator and denominator is a single digit number.
ii) The sum of my numerator and denominator is a multiple of 3.
iii) The product of my numerator and denominator is a multiple of 4.

Sum

Solution

The numerator may be any one of 1, 2, 3, 4, 5, 6, 7, 8, 9 and the denominator may be any one of 1, 2, 3, 4, 5, 6, 7, 8, 9.

Sum of numerator and denominator is a multiple of 3.

∴ Possible proper fractions are `1/2, 1/5, 1/8, 2/4, 2/7, 3/6, 3/9, 4/5, 4/8, 5/7, 6/9`

Also given the product of numerator and denominator is a multiple of 4.

∴ Possible fractions are `1/8, 2/4, 4/5, 4/8`

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Chapter 1: Fractions - Exercise 1.2 [Page 21]

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Samacheer Kalvi Mathematics - Term 3 [English] Class 6 TN Board
Chapter 1 Fractions
Exercise 1.2 | Q 6 | Page 21
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