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Question
Calculate the mass of Calcium that will contain the same number of the atom as are present in 3.2 gm of Sulphur.
[Atomic masses: S=32, Ca=40]
Solution
Given:
Mass of Sulphur = 3.2 gm
Solution:
32 g of S ≡ 6.022 × 1023 atoms
3.2 g of S ≡?
3.2 g of S will contain =` (6.022 xx 10^23 xx 3.2)/32` = 6.022 x 1022 atoms
40 g of Ca ≡ 6.022 × 1023 atoms
`?≡6.022 xx 10^22` atoms
Mass of Ca ≡ `(6.022 xx 10^22 xx 40)/(6.022 xx 10^(23))` = 4g
Mass of calcium = 4g
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