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Question
Calculate the magnetic field at the center of a square loop which carries a current of 1.5 A, length of each loop is 50 cm.
Solution
Current through the square loop, I = 1.5A
Length of each loop, l = 50cm 50 x 10-2 m
According to Biot-Savart Law.
Magnetic field due to a current-carrying straight wire
B = `(mu_0"I")/(4pi"a") (sin alpha + sin beta)`
`= (4pi xx 10^-7 xx 1.5)/(4pi xx (l/2)) (sin45^circ + sin 45^circ)`
`= (2 xx 1.5 xx 10^-7)/"l"(1/sqrt2 + 1/sqrt2)`
`= (2 xx 1.5xx10^-7)/(50xx10^-2)(2/sqrt2)`
B =0.084866 x 10-5 T
Magnetic field at a point p? of centre of current carrying square loop
B’ =4 sides x B
= 4 x 0.08487 x 10-5 = 0.33948 x 10-5
B’ =3.4 x 10-6 T
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