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Question
Calculate the mass defect and the binding energy per nucleon of the \[\ce{^108_47Ag}\] nucleus. [atomic mass of Ag = 107.905949].
Solution
Mass of proton, mp = 1.007825 amu
Mass of neutron, mn = 1.008665 amu
Mass defect, ∆m = Zmp + Z mN – MN
= 47 x 1.007825 + 61 x 1.008665 – 107.905949
= 108.89634- 107.905949
∆m = 0.990391 u
Binding energy per nucleon of the \[\ce{^108_47Ag}\] nucleus.
`bar"B.E" = (Delta "m" xx 931)/"A" = (0.990391 xx 931)/108`
`= (922.054021)/108 = 8.537`
`bar"B.E" = 8.5 "MeV"/"A"`
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