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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Half-lives of two radioactive elements A and B are 20 minutes and 40 minutes respectively. Initially, the samples have equal number of nuclei. - Physics

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Question

Half-lives of two radioactive elements A and B are 20 minutes and 40 minutes respectively. Initially, the samples have equal number of nuclei. Calculate the ratio of decayed numbers of A and B nuclei after 80 minutes.

Numerical

Solution

(T1/2)A = 20 minutes

(T1/2)B = 40 minutes

t = 80 minutes

n = `"t"/("T"_(1/2))` N = `"N"_circ (1/2)^"n" = "t"/("T"_(1/2))`

For A : nA = `80/20 = 4`

`"N"_"A" = "N"_circ (1/2)^4 = "N"_circ/16`

Number of A Nucleided decayed = 

`"N"_circ - "N"_circ/16 = (15"N"_circ)/16`

For B : nB = `80/40 = 2`

`"N"_"B" = "N"_circ (1/2)^2 = "N"_circ/4`

Number of A Nucleided decayed = 

`"N"_circ - "N"_circ/4 = (3"N"_circ)/4`

`"N"_"A"/"N"_"B" = (15"N"_circ)/16 xx 4/(3 "N"_circ) = 5/4`

`"N"_"A"/"N"_"B" =` 5 : 4

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Radioactivity
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Chapter 9: Atomic and Nuclear physics - Evaluation [Page 192]

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Samacheer Kalvi Physics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 9 Atomic and Nuclear physics
Evaluation | Q 6. | Page 192
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