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Question
Half-lives of two radioactive elements A and B are 20 minutes and 40 minutes respectively. Initially, the samples have equal number of nuclei. Calculate the ratio of decayed numbers of A and B nuclei after 80 minutes.
Solution
(T1/2)A = 20 minutes
(T1/2)B = 40 minutes
t = 80 minutes
n = `"t"/("T"_(1/2))` N = `"N"_circ (1/2)^"n" = "t"/("T"_(1/2))`
For A : nA = `80/20 = 4`
`"N"_"A" = "N"_circ (1/2)^4 = "N"_circ/16`
Number of A Nucleided decayed =
`"N"_circ - "N"_circ/16 = (15"N"_circ)/16`
For B : nB = `80/40 = 2`
`"N"_"B" = "N"_circ (1/2)^2 = "N"_circ/4`
Number of A Nucleided decayed =
`"N"_circ - "N"_circ/4 = (3"N"_circ)/4`
`"N"_"A"/"N"_"B" = (15"N"_circ)/16 xx 4/(3 "N"_circ) = 5/4`
`"N"_"A"/"N"_"B" =` 5 : 4
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