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Question
Calculate the mass of silver deposited at cathode when a current of 2 amperes is passed through a solution of AgNO3 for 15 minutes.
(at. wt. of Ag= 108, 1F = 96500 C)
Sum
Solution
w = z.I.t
A = 108, E = `"A"/1 = 108/1 = 108`
z = `"E"/96500 = 108/96500 "g"//"c"`
I = 2 amperes
t = 15 × 60 = 900 sec.
w = `108/96500 xx 2 xx 900` g
`=(216 xx 9)/965 = 1944/965 = 2.014`
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States of Matters: Structure and Properties Solid State - Calculation of the Number of Atoms per Unit Cell
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