Advertisements
Advertisements
Question
Calculate the mean of the scores of 20 students in a mathematics test:
Marks | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 |
Number of students |
2 | 4 | 7 | 6 | 1 |
Solution
We first, find the class mark xi of each class and then proceed as follows.
Marks | Class marks `(bb(x_i))` |
Frequency `(bb(f_i))` |
`bb(f_ix_i)` |
10 – 20 | 15 | 2 | 30 |
20 – 30 | 25 | 4 | 100 |
30 – 40 | 35 | 7 | 245 |
40 – 50 | 45 | 6 | 270 |
50 – 60 | 55 | 1 | 55 |
`sumf_i = 20` | `sumf_ix_i = 700` |
Therefore, mean `(barx) = (sumf_ix_i)/(sumf_i)`
= `700/20`
= 35
Hence, the mean of scores of 20 students in mathematics test is 35.
APPEARS IN
RELATED QUESTIONS
If the mean of the following data is 15, find p.
x | 5 | 10 | 15 | 20 | 25 |
f | 6 | P | 6 | 10 | 5 |
For the following distribution, calculate mean using all suitable methods:
Size of item | 1 - 4 | 4 - 9 | 9 - 16 | 16 - 27 |
Frequency | 6 | 12 | 26 | 20 |
The following table shows the marks scored by 140 students in an examination of a certain paper:
Marks: | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
Number of students: | 20 | 24 | 40 | 36 | 20 |
Calculate the average marks by using all the three methods: direct method, assumed mean deviation and shortcut method.
Find the mean of the following data, using direct method:
Class | 0-100 | 100-200 | 200-300 | 300-400 | 400-500 |
Frequency | 6 | 9 | 15 | 12 | 8 |
Find the mean of the following data, using step-deviation method:
Class | 5 – 15 | 15-20 | 20-35 | 35-45 | 45-55 | 55-65 | 65-75 |
Frequency | 6 | 10 | 16 | 15 | 24 | 8 | 7 |
If the mean of first n natural numbers is `(5n)/9,` then n =?
If the mean of observations x1, x2, x3, ....xn is `barx,` then the mean of new observations x1 + a, x2 + a, x3 + a, ........ xn + a is?
Calculate the mean of the following data:
Class | 4 – 7 | 8 – 11 | 12 – 15 | 16 – 19 |
Frequency | 5 | 4 | 9 | 10 |
Find the mean of the following frequency distribution:
Class | 1 – 5 | 5 – 9 | 9 – 13 | 13 – 17 |
Frequency | 4 | 8 | 7 | 6 |
The following table gives the marks scored by a set of students in an examination. Calculate the mean of the distribution by using the short cut method.
Marks | Number of Students (f) |
0 – 10 | 3 |
10 – 20 | 8 |
20 – 30 | 14 |
30 – 40 | 9 |
40 – 50 | 4 |
50 – 60 | 2 |