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Question
Calculate the number of moles and number of molecules present in 1.4 g of ethylene gas. What is the volume occupied by the same amount of ethylene?
Solution
Molecular mass of ethylene (CH2-CH2) = 1.4 g
Number of moles = `"Mass"/"Molecular mass"`
= `1.4/28`
= 0.05 moles
Now, number of molecules in 1 mole = 6.023 × 1023
∴ Number of molecules in 0.05 moles = 6.023 x 1023 × 0.05
= 0.3 × 1023
= 3 × 1022 molecules
Volume occupied by 1 mole of ethylene = 22.4 L
∴ Volume occupied by 0.05 moles of ethylene = 22.4 × 0.05
= 1.12 L
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