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Question
Calculate the strength of 5 volume \[\ce{H2O2}\] solution.
Solution
5 volume \[\ce{H2O2}\] solution means that 1 L of 5 volume \[\ce{H2O2}\] on decomposition gives 5L of \[\ce{O2}\] at NTP.
\[\ce{\underset{68 g}{H2O2} -> \underset{22.4 L at NTP}{2H2O + O2}}\]
22.4 L of \[\ce{O2}\] at NTP is produced from \[\ce{H2O2}\] = 68 g
5 L of O2 at NTP is produced from H2O2 = `68/22.4 xx 5` = 15.18 g
But 5 L of \[\ce{O2}\] at NTP is produced from 1 L of 5 volume \[\ce{H2O2}\]
Strength of \[\ce{H2O2}\] in 5 volume \[\ce{H2O2}\] = 15.18 g/L
Percentage strength of H2O2 solution = `15.18/1000 xx 100` = 1.518%
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