Advertisements
Advertisements
Question
Calculate the value of magnetic field at a distance of 3 cm from a very long, straight wire carrying a current of 6 A.
Solution
Given,
R = 3 cm = 3 × 10-2 m
I = 6 A
B = ?
Magnetic field B = `(mu_0 "l")/(2 pi "R")`
`= (4 pi xx 10^-7 xx 6)/(2 pi xx 3 xx 10^-2)`
B = 4 × 10-5 T
The value of a magnetic field is 4 × 10-5 T.
APPEARS IN
RELATED QUESTIONS
A piece of straight wire has mass 20 g and length 1 m. It is to be levitated using a current of 1 A flowing through it and a perpendicular magnetic field B in a horizontal direction. What must be the magnitude B of the magnetic field?
A horizontal rod of mass 20 g and length 40 cm is placed on a smooth plane inclined at an angle of 60° with the horizontal, with the length of the rod parallel to the edge of the inclined plane. A uniform magnetic field of induction B is applied vertically downwards. If the current through the rod is 1.73 ampere, then the value of B for which the rod remains stationary on the inclined plane is ____________.
A straight wire of length 50 cm carrying a current of 6 A is suspended in mid-air by a uniform magnetic field of 0.4 T (as shown in figure). The mass of the wire is ______.
(g = 10` "ms"^-2`)
A straight wire of length 0.5 m and carrying current of 1.2A is placed in a uniform magnetic field of induction 2T. The magnetic field is perpendicular to the length of the wire. What is the force acting on the wire? sin 90° = 1
A long straight wire in the horizontal plane carries a current of 75 A in north of south direction, magnitude and direction of field B at a point 3 m east of the wire is ______.
A bomb at rest explodes into 3 parts of the same mass. The momentum of the two parts is `-3"P"hat"i"` and `2"P"hat"J"` respectively. The magnitude of the momentum of the third part is ______.