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Question
Calculate the work done when 2 moles of an ideal gas expands reversibly and isothermally from a volume of 500 ml to a volume of 2 L at 25°C and normal pressure.
Solution
Given: n = 2 moles
Vi = 500 ml = 0.5 lit
Vf = 2 lit
T = 25°C = 298 K
w = − 2.303 nRT log `("V"_"f"/"V"_"i")`
w = `-2.303 xx 2 xx 8.314 xx 298 xx log (2/0.5)`
w = − 2.303 × 2 × 8.314 × 298 × log (4)
w = − 2.303 × 2 × 8.314 × 298 × 0.6021
w = − 6871 J
w =− 6.871 kJ
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