Advertisements
Advertisements
Question
Check whether 422 is in the sequence 10, 13, 16, 19, 22, ....
Solution
Given sequence is 10, 13, 16, 19, 22, .....
Here, t1 = 10, t2 = 13, t3 = 16
Now, t2 – t1 = 13 – 10 = 3
And t3 – t2 = 16 – 13 = 3
∵ t2 – t1 = t3 – t2
∴ This sequence is an A.P.
So, First term, a = 10
Common Difference, d = 3
Let 422 be its nth term.
Then, tn = a + (n – 1)d
⇒ 422 = 10 + (n – 1)3
⇒ 422 = 10 + 3n – 3
⇒ 422 = 7 + 3n
⇒ 422 – 7 = 3n
⇒ 415 = 3n
⇒ n = 138.333
However, it is not an integer.
As a result, 422 is not in the specified sequence.
APPEARS IN
RELATED QUESTIONS
If A = {11, 21, 31, 41}, B = {12, 22, 31, 32}, then find:
(1) A ∪ B
(2) A ∩ B
Find the first two terms of the following sequence:
tn = n +2 .
State whether the following sequence is an A.P. or not.
1,3,6,10,......
tn = 2n − 5 in a sequence, find its first two terms
Find first term of the sequence tn = 2n + 1
Find two terms of the sequence tn = 3n – 2
Find first four terms of the sequence tn = n + 2
Kalpana saves some amount every month. In the first three months, she saves ₹ 100, ₹ 150, and ₹ 200 respectively. In how many months will she save ₹ 1200?
Activity :- Kalpana’s monthly saving is ₹ 100, ₹ 150, ₹ 200, ......, ₹ 1200
Here, d = 50. Therefore this sequence is an A.P.
a = 100, d = 50, tn = `square`, n = ?
tn = a + (n – 1) `square`
`square` = 100 + (n – 1) × 50
`square/50` = n – 1
n = `square`
Therefore, she saves ₹ 1200 in `square` months.
Which of the following sequence form an A.P.?
Find two consecutive positive even integers such that their product is 1520.
What will be the 6th, 12th and 25th term of the sequence defined by an = (n – 2)2 + 2n?