Question

Complete the addition-subtraction box.

Answer 1

${\displaystyle \frac{2}{3}+\frac{4}{3}}$

= ${\displaystyle \frac{(2+4)}{3}}$

= ${\displaystyle \frac{6}{3}}$

= 2

${\displaystyle \frac{1}{3}+\frac{2}{3}}$

= ${\displaystyle \frac{(1+2)}{3}}$

= ${\displaystyle \frac{3}{3}}$

= 1

${\displaystyle \frac{2}{3}-\frac{1}{3}}$

= ${\displaystyle \frac{(2-1)}{3}}$

= ${\displaystyle \frac{1}{3}}$

${\displaystyle \frac{4}{3}-\frac{2}{3}}$

= ${\displaystyle \frac{(4-2)}{3}}$

= ${\displaystyle \frac{2}{3}}$

${\displaystyle \frac{1}{3}+\frac{2}{3}}$

= ${\displaystyle \frac{(1+2)}{3}}$

= ${\displaystyle \frac{3}{3}}$

= 1

Hence, the complete given box is