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Question
Compute mean deviation about median from the following data:
Height in inches | No. of students |
58 | 15 |
59 | 20 |
60 | 32 |
61 | 35 |
62 | 35 |
63 | 22 |
64 | 20 |
65 | 10 |
66 | 8 |
Solution
X | f | cf |
58 | 15 | 15 |
59 | 20 | 35 |
60 | 32 | 67 |
61 | 35 | 102 |
62 | 35 | 137 |
63 | 22 | 159 |
64 | 20 | 179 |
65 | 10 | 189 |
66 | 8 | 197 |
N = 197 |
Median = Size of `(("N" + 1)/2)^"th"` value
= Size of `((197 + 1)/2)^"th"` value
= Size of `(198/2)^"th"` value
= Size of 99th value
= 99th item
= 61
MD about median = `(sum"f" |"X" - "Median"|)/"N" = (sum"f" |"D"|)/"N"`
Mean deviation about median:
X | f |
|D| = `|"X" - bar"X"|` |
f|D| |
58 | 15 | 3 | 45 |
59 | 20 | 2 | 40 |
60 | 32 | 1 | 32 |
61 | 35 | 0 | 0 |
62 | 35 | 1 | 35 |
63 | 22 | 2 | 44 |
64 | 20 | 3 | 60 |
65 | 10 | 4 | 40 |
66 | 8 | 5 | 40 |
N = 197 | ∑f|D| = 336 |
MD about median = `(sum"f" |"D"|)/"N" = 336/197` = 1.70558 = 1.71
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