Advertisements
Advertisements
Question
If median = 45 and its coefficient is 0.25, then the mean deviation about median is
Options
11.25
180
0.0056
45
Solution
11.25
Explanation:
Coefficient of M.D = `"MD"/"Median"`
MD = Coefficient of MD × Median
= 0.25 × 45
= 11.25
APPEARS IN
RELATED QUESTIONS
Calculate the quartile deviation and its coefficient from the following data:
| Age in Years: | 20 | 30 | 40 | 50 | 60 | 70 | 80 |
| No. of Members: | 13 | 61 | 47 | 15 | 10 | 18 | 36 |
Calculate quartile deviation and its relative measure from the following data:
| X | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 |
| f | 5 | 10 | 13 | 18 | 14 | 8 |
Compute mean deviation about median from the following data:
| Height in inches | No. of students |
| 58 | 15 |
| 59 | 20 |
| 60 | 32 |
| 61 | 35 |
| 62 | 35 |
| 63 | 22 |
| 64 | 20 |
| 65 | 10 |
| 66 | 8 |
Compute the mean deviation about mean from the following data:
| Class Interval: | 0 - 5 | 5 - 10 | 10 - 15 | 15 - 20 | 20 - 25 |
| Frequency (f) | 3 | 5 | 12 | 6 | 4 |
Find out the coefficient of mean deviation about median in the following series.
| Age in years | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 | 60 - 70 | 70 - 80 |
| No. of persons | 8 | 12 | 16 | 20 | 37 | 25 | 19 | 13 |
If Q1 = 30 and Q3 = 50, the coefficient of quartile deviation is
Calculate the Mean deviation about median of the following data.
| Class interval: | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 |
| Frequency: | 6 | 7 | 15 | 16 | 4 | 2 |
Calculate Mean deviation about Mean of the following data.
| X | 2 | 5 | 6 | 8 | 10 | 12 |
| f | 2 | 8 | 10 | 7 | 8 | 5 |
Calculate Quartile deviation and Coefficient of Quartile deviation of the following data.
| Marks: | 0 | 10 | 20 | 30 | 40 | 50 | 60 | 70 |
| No. of students: | 150 | 142 | 130 | 120 | 72 | 30 | 12 | 4 |
What is dispersion?
