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Question
Construct a parallelogram ABCD, if :
diagonal AC = 6.4 cm, diagonal BD = 5.6 cm and angle between the diagonals is 75°.
Solution
The rough figure is as follows.
∵ Diagonals of || gm bisect each other.
∴ OB = OD = `1/2`BD = 2.8 cm.
The actual figure is constructed with the help of the above figure as follows.
Steps :
- Draw AC = 6.4 cm.
- Bisect AC at O.
- Draw ∠XOC = 75° and produce XO to Y.
- Cut OB = OD = 2 8 cm.
- Join AB, BC, AD, and CD.
Thus ABCD is the required ||gm.
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