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Question
Construct a square in which each diagonal is 5 cm long.
Solution
Steps of construction:
Step I: Draw AC = 5 cm.
Step II: With A as centre, draw arc of length slightly greater than `1/2` AC above and below the line segment AC.
Step III: With C as centre, draw an arc of same length as in step II above and below the line segment AC that is intersect the arcs drawn in step II.
Step IV: Join both the intersection points obtained in step III by a line segment that is intersect AC at O.
Step V: With O as centre cut-off OB = OD = 2.5 cm along the bisector line.
Step VI: Join AD, CD, AB and CB.
Hence, ABCD is a required square.
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