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Construct a trapezium ABCD in which AB || DC, ∠A = 105°, AD = 3 cm, AB = 4 cm and CD = 8 cm. - Mathematics

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Question

Construct a trapezium ABCD in which AB || DC, ∠A = 105°, AD = 3 cm, AB = 4 cm and CD = 8 cm.

Sum

Solution

We know that,


∠A + ∠D = 180°   ...[Sum of adjacent angle of a trapezium is 180°]

105° + ∠D = 180°

∠D = 180° – 105°

∠D = 75°

Steps of construction:

Step I: Draw AB = 4 cm.

Step II: Draw `bar(AX)` that is ∠BAX = 105°.

Step III: Mark a point D on AX that is AD = 3 cm.

Step IV: Draw `bar(DY)` that is ∠ADY = 75°.

Step V: Mark a point C that is CD = 8 cm.

Step VI: Join BC.

Hence, ABCD is the required trapezium.

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Chapter 5: Understanding Quadrilaterals and Practical Geometry - Exercise [Page 162]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 5 Understanding Quadrilaterals and Practical Geometry
Exercise | Q 186 | Page 162

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