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Question
Construct any ΔABC. Construct ΔA'BC' such that AB : A'B = 5 : 3 and ΔABC ∼ ΔA'BC'.
Solution
Steps of construction:
- Draw ΔABC in any size.
- Extend the AB and CB rays.
- Segment AB should be divided into 5 equal sections.
- Measure one equal part (of segment AB) on the compass and draw three arcs on extended ray AB beginning at point B.
- A' represents the intersection of the third arc and the extended ray AB.
- Draw a line parallel to AC from A'.
- C' is the point of intersection of this line and the extended ray CB. As a result, ΔA'BC' is the needed triangle, which is comparable to ΔABC.
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