English

Geometry Mathematics 2 Model set 2 by shaalaa.com 2024-2025 SSC (English Medium) 10th Standard Board Exam Question Paper Solution

Advertisements
Geometry Mathematics 2 [Model set 2 by shaalaa.com]
Marks: 40 Maharashtra State Board
SSC (English Medium)
SSC (Marathi Semi-English)

Academic Year: 2024-2025
Date: March 2025
Advertisements

General Instructions :

  1. All questions are compulsory.
  2. Use of a calculator is not allowed.
  3. The numbers to the right of the questions indicate full marks.
  4. In case of MCQs (Q. No. 1(A)) only the first attempt will be evaluated and will be given credit.
  5. For every MCQ, the correct alternative (A), (B), (C) or (D) with subquestion number is to be written as an answer.
  6. Draw proper figures for answers wherever necessary.
  7. The marks of construction should be clear. Do not erase them.
  8. Diagram is essential for writing the proof of the theorem.

[8]1
[4]1.A | For each of the following sub-questions four alternatives answers are given. Choose the correct alternative and write its alphabet :
[1]1.A.i

Find the value of sin 0° + cos 0° + tan 0° + sec 0°.

2

1

3

0

Concept: undefined - undefined
Chapter: [0.06] Trigonometry
[1]1.A.ii

If x = `θ/360` × 2πr then what is x in the formula?

Length of the arc of measure θ

Area of sector of measure θ

Area of the segment of measure θ

The circumference of the circle

Concept: undefined - undefined
Chapter: [0.07] Mensuration
[1]1.A.iii

In the adjoining figure, a tangent is drawn to a circle of radius 4 cm and centre C, at the point S. Find the length of the tangent ST, if CT = 10 cm.

`sqrt(21)` cm

`3sqrt(21)` cm

`2sqrt(21)` cm

`4sqrt(21)` cm

Concept: undefined - undefined
Chapter: [0.02] Pythagoras Theorem
[1]1.A.iv

Find the length of ST, if ΔPQR ∼ ΔPST.

7.2 cm

7 cm

8 cm

9 cm

Concept: undefined - undefined
Chapter: [0.01] Similarity
[4]1.B | Solve the following subquestions :
[1]1.B.i

Two opposite angles of a parallelogram are (2x + 60)° and (4x)°. Find the value of x.

Concept: undefined - undefined
Chapter: [0.03] Circle
[1]1.B.ii

A line is parallel to Y-axis and is at a distance of 5 units from the Y-axis. Write the equation of that line.

Concept: undefined - undefined
Chapter: [0.05] Co-ordinate Geometry
[1]1.B.iii

Find will be the value of cos 90° + sin 90°.

Concept: undefined - undefined
Chapter: [0.06] Trigonometry
[1]1.B.iv

In a parallelogram ABCD, ∠B = 105°. Determine the measure of ∠A and ∠D.

Concept: undefined - undefined
Chapter: [0.03] Circle
[12]2
Advertisements
[4]2.A | Complete the following activities and rewrite it (any two)
[2]2.A.i

In the figure, PQ ⊥ BC, AD ⊥ BC. To find the ratio of A(ΔPQB) and A(ΔPBC), complete the following activity.


Given: PQ ⊥ BC, AD ⊥ BC

Now, A(ΔPQB)  = `1/2 xx square xx square`

A(ΔPBC)  = `1/2 xx square xx square`

Therefore, 

`(A(ΔPQB))/(A(ΔPBC)) = (1/2 xx square xx square)/(1/2 xx square xx square)`

= `square/square`

Concept: undefined - undefined
Chapter: [0.01] Similarity
[2]2.A.ii

The radius of a metal sphere is 3 cm. The sphere is melted and made into a long wire of uniform circular cross-section, whose length is 36 cm. To calculate the radius of wire, complete the following activity.

Radius of the sphere = `square`

Length of the wire = `square`

Let the radius of the wire by r cm.

Now, Volume of the wire = Volume of the `square`

`square` = `square`

r2 × `square` = `square` × `square`

r2 × `square` = `square`

r = `square`

Hence, the radius of the wire is `square` cm.

Concept: undefined - undefined
Chapter: [0.07] Mensuration
[2]2.A.iii

From the information in the figure, complete the following activity to find the length of the hypotenuse AC.


AB = BC = `square`

∴ ∠BAC = `square`

Side opposite angle 45° = `square/square` × Hypotenuse

∴ `5sqrt(2) = 1/square` × AC

∴ AC = `5sqrt(2) xx square = square`

Concept: undefined - undefined
Chapter: [0.02] Pythagoras Theorem
[8]2.B | Solve the following subquestions (any four) :
[2]2.B.i

In the figure, ΔPQR is right angled at Q, seg QS ⊥ seg PR. Find x, y.

Concept: undefined - undefined
Chapter: [0.02] Pythagoras Theorem
[2]2.B.ii

Draw a circle of suitable radius. Take point T on it. Draw a tangent through point T.

Concept: undefined - undefined
Chapter: [0.04] Geometric Constructions
[2]2.B.iii

In a right angled triangle, right-angled at B, lengths of sides AB and AC are 5 cm and 13 cm, respectively. What will be the length of side BC?

Concept: undefined - undefined
Chapter: [0.02] Pythagoras Theorem
[2]2.B.iv

A tangent JK is drawn to a circle with centre C such that CK = 6 cm and ∠CKJ = 60°. Find the length of the tangent JK.

Concept: undefined - undefined
Chapter: [0.03] Circle
[2]2.B.v

If ΔABC ∼ ΔDEF, length of side AB is 9 cm and length of side DE is 12 cm, then find the ratio of their corresponding areas.

Concept: undefined - undefined
Chapter: [0.01] Similarity
[9]3
[3]3.A | Complete the following activity and rewrite it (any one)
Advertisements
[3]3.A.i

Find distance between points P(– 5, – 7) and Q(0, 3).

By distance formula,

PQ = `sqrt(square + (y_2 - y_1)^2`

= `sqrt(square + square)`

= `sqrt(square + square)`

= `sqrt(square + square)`

= `sqrt(125)`

= `5sqrt(5)`

Concept: undefined - undefined
Chapter: [0.05] Co-ordinate Geometry
[3]3.A.ii

If cot θ = `40/9`, find the values of cosec θ and sinθ,

We have, 1 + cot2θ = cosec2θ

1 + `square` = cosec2θ

1 + `square` = cosec2θ

`(square + square)/square` = cosec2θ

`square/square` = cosec2θ  ......[Taking root on the both side]

cosec θ = `41/9`

and sin θ = `1/("cosec"  θ)`

sin θ = `1/square`

∴ sin θ =  `9/41`

The value is cosec θ = `41/9`, and sin θ = `9/41`

Concept: undefined - undefined
Chapter: [0.06] Trigonometry
[6]3.B | Solve the following subquestions (any two) :
[3]3.B.i

Construct any ΔABC. Construct ΔA'BC' such that AB : A'B = 5 : 3 and ΔABC ∼ ΔA'BC'.

Concept: undefined - undefined
Chapter: [0.04] Geometric Constructions
[3]3.B.ii

Draw ΔRSP ∼ ΔTQP. In ΔTQP, TP = 5 cm, ∠P = 50°, PQ = 4.5 cm and `("RS")/("TQ") = 2/3`.

Concept: undefined - undefined
Chapter: [0.04] Geometric Constructions
[3]3.B.iii

In the given figure, Sand Tare points on sides PQ and PR, respectively of ΔPQR such that ST is parallel to QR and SQ = TR. Prove that ΔPQR is an isosceles triangles.

Concept: undefined - undefined
Chapter: [0.01] Similarity
[3]3.B.iv

A figure is in the form of rectangle PQRS having a semi-circle on side QR as shown in the figure. Determine the area of the plot.

Concept: undefined - undefined
Chapter: [0.03] Circle
[8]4 | Solve the following subquestions (any two) :
[4]4.A

In the following figure, a quadrilateral LMNO circumscribes a circle with centre C. ∠O = 90°, LM = 25 cm, LO = 27 cm and MJ = 6 cm. Calculate the radius of the circle.

Concept: undefined - undefined
Chapter: [0.03] Circle
[4]4.B

The dimensions of a cuboid are 44 cm, 21 cm, 12 cm. It is melted and a cone of height 24 cm is made. Find the radius of its base.

Concept: undefined - undefined
Chapter: [0.07] Mensuration
[4]4.C

Given: O is the centre of the circle, AB is a diameter, OA = AP, O – A – P, PC is a tangent through C. A tangent through point A intersects PC in E and BC in D.

To prove: ΔCED is an equilateral triangle.

Concept: undefined - undefined
Chapter: [0.04] Geometric Constructions
[3]5 |  Solve the following subquestions (any one) :
[3]5.A

A tent is a shape of a triangular 'prism' resting on a rectangular side PQ = PR, PT = 1.5 m, QR = 1.8 m, length of the tent = 3 m. Find:

  1. ∠PQR
  2. The volume of the tent

Concept: undefined - undefined
Chapter: [0.07] Mensuration
[3]5.B

A pizza has 8 slices all equally spaced. Suppose pizza is a flat circle of radius 28 cm, find the area covered between 3 slices of pizza.

Concept: undefined - undefined
Chapter: [0.03] Circle

Other Solutions





















Submit Question Paper

Help us maintain new question papers on Shaalaa.com, so we can continue to help students




only jpg, png and pdf files

Maharashtra State Board previous year question papers 10th Standard Board Exam Geometry Mathematics 2 with solutions 2024 - 2025

     Maharashtra State Board 10th Standard Board Exam Geometry Maths 2 question paper solution is key to score more marks in final exams. Students who have used our past year paper solution have significantly improved in speed and boosted their confidence to solve any question in the examination. Our Maharashtra State Board 10th Standard Board Exam Geometry Maths 2 question paper 2025 serve as a catalyst to prepare for your Geometry Mathematics 2 board examination.
     Previous year Question paper for Maharashtra State Board 10th Standard Board Exam Geometry Maths 2-2025 is solved by experts. Solved question papers gives you the chance to check yourself after your mock test.
     By referring the question paper Solutions for Geometry Mathematics 2, you can scale your preparation level and work on your weak areas. It will also help the candidates in developing the time-management skills. Practice makes perfect, and there is no better way to practice than to attempt previous year question paper solutions of Maharashtra State Board 10th Standard Board Exam.

How Maharashtra State Board 10th Standard Board Exam Question Paper solutions Help Students ?
• Question paper solutions for Geometry Mathematics 2 will helps students to prepare for exam.
• Question paper with answer will boost students confidence in exam time and also give you an idea About the important questions and topics to be prepared for the board exam.
• For finding solution of question papers no need to refer so multiple sources like textbook or guides.
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×