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Question
Construct a triangle similar to a given ΔXYZ with its sides equal to (3/4)th of the corresponding sides of ΔXYZ. Write the steps of construction.
Solution
let XY = cm, YZ = cm and ∠Y = 60° and then a triangle similar to it whose sides are (3/4)th of the corrosponding sides of ΔXYZ
we follow the following steps to construct triangle.
Step of construction
step 1. First of all we draw a line segment XY = 5 cm
step 2. With Y as centre on angle ∠Y = 60°
step 3. with Y as centre and radius YZ = 6 cm, draw on arc
step 4. Join XZ to obtain ΔXYZ
step 5. Below XY1 makes an acute angle ∠YXL = 60°
step 6. Below XL, mark off four points X1, X2, X3 and X4 such that XX1 = X1X2 = X2X3 = X3X4
step 7. Join X4Y
step 8. since we have to construct a triangle each of whose sides is (3/4)th of the corresponding sides of ΔXYZ
So, we take three parts out of four equal parts on XL from point X3 draw X3Y' || X4Y and meeting XY at Y'
step 9. From Y' draw Y'Z' || YZ, and meeting XZ at Z'
Hence, ΔXY'Z' is the required triangle, each of whose sides is (3/4)th of the corresponding sides of ΔXYZ
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