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Question
To divide a line segment AB in the ratio 5 : 7, first a ray AX is drawn so that ∠BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is ______.
Options
8
10
11
12
Solution
To divide a line segment AB in the ratio 5 : 7, first a ray AX is drawn so that ∠BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is 12.
Explanation:-
We know that to divide a line segment in the ratio m : n, first draw a ray AX which makes an acute angle BAX, then marked m + n points at equal distances from each other.
Here m = 5, n = 7
So minimum number of these point = m + n = 5 + 7 = 12
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