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To construct a triangle similar to a given ΔABC with its sides 8/5 of the corresponding sides of ΔABC draw a ray BX such that ∠CBX is an acute angle - Mathematics

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Question

To construct a triangle similar to a given ΔABC with its sides `8/5` of the corresponding sides of ΔABC draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. Then minimum number of points to be located at equal distances on ray BX is ______.

Options

  • 5

  • 8

  • 13

  • 3

MCQ
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Solution

To construct a triangle similar to a given ΔABC with its sides `8/5` of the corresponding sides of ΔABC draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. Then minimum number of points to be located at equal distances on ray BX is 8.

Explanation:

To construct a triangle similar to a given triangle, with its sides `m/n` of the corresponding sides of given triangle the minimum number of points to be located at equal distance is equal to the greater of m and n in `m/n`.

Here, `m/n=8/5`

So, the minimum number of points to be located at equal distance on ray BX is 8.

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Chapter 10: Construction - Exercise 10.1 [Page 114]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 10
Chapter 10 Construction
Exercise 10.1 | Q 5 | Page 114

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Solution:

Point P divides segment AB in the ratio m: n.

A(8, 9) = (x1, y1), B(1, 2 ) = (x2, y2) and P(6, 7) = (x, y)

Using Section formula of internal division,

∴ 7 = `("m"(square) - "n"(9))/("m" + "n")`

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∴ 7m – `square` = 9n – `square`

∴ `square` = 2n

∴ `"m"/"n" = square`


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