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Question
Draw a right triangle in which the sides (other than the hypotenuse) are of lengths 4 cm and 3 cm. Now construct another triangle whose sides are `3/5` times the corresponding sides of the given triangle.
Solution
Construct a right triangle of sides AB = 4 cm, AC = 3 cm and ∠A = 90° and then a triangle similar to it whose sides are `(3/5)^"th"` of the corresponding sides of ΔABC
We follow the following steps to construct the given
Step of construction
Step: I- First of all we draw a line segment AB = 4 cm.
Step: II- With A as centre and draw an angle ∠A = 90°.
Step: III- With A as centre and radius AC = 3 cm.
Step: IV-Join BC to obtain right ΔABC.
Step: V- Below AB, makes an acute angle ∠BAX.
Step: VI- Along AX, mark off five points A1, A2, A3, A4 and A5 such that =A4A5.
Step: VII- Join A5B.
Step: VIII -Since we have to construct a triangle each of whose sides is (`3/5`)th of the corresponding sides of right ΔABC
So, we draw a line on AX from point which is A3B ∥ A5B and meeting AB at B’.
Step: IX- From B’ point draw B'C' || BCand meeting AC at C’
Thus, ΔABC is the required triangle, each of whose sides is `(3/5)`th of the corresponding sides of ΔABC.
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