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Question
Determine the nature of the roots of the following quadratic equation:
`3x^2-2sqrt6x+2=0`
Solution
The given quadric equation is `3x^2-2sqrt6x+2=0`
Here, a = 3, `b=-2sqrt6` and c = 2
As we know that D = b2 - 4ac
Putting the value of a = 3, `b=-2sqrt6` and c = 2
`D = (-2sqrt6)^2-4xx3xx2`
= 24 - 24
= 0
Since, D = 0
Therefore, root of the given equation are real and equal.
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