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Question
Determine the region in the plane determined by the inequalities:
2x + 3y ≤ 6, x + 4y ≤ 4, x ≥ 0, y ≥ 0
Solution
If 2x + 3y = 6
| x | 0 | 3 |
| y | 2 | 0 |
x + 4y = 4
| x | 0 | 4 |
| y | 1 | 0 |
x ≥ 0, y ≥ 0 represents the area in the 1 quadrant.
The required region is below 2x + 3y = 6 and below x + 4y = 4 bounded by x-axis and y-axis.
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