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Question
Differentiate the following w. r. t. x. : x3 .3x
Solution
Let y = x3 3x
Differentiating w.r.t. x, we get
`dy/dx = d/dx (x^3 3^x)`
= `x^3d/dx(3^x) + 3^x d/dx(x^3)`
= (x3)(3x log 3) + 3x(3x2)
= x2 3x (xlog3 + 3)
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